大学物理相对论论文1000字高清

文稿 应具备有科学性，实用性，论点明确，文字精炼，层次清楚，数据准确、规范。论著、综述一般不超过5000字，一般栏目稿件勿超过4000字，小经验稿件不超过1000字。　　2 文题 力求简明、醒目，反映出文章的主题。中文文题以不超过20个汉字为宜。3 作者姓名 在文题下按贡献大小排列，作者单位名称及邮政编码注于同页左下方，并附第一作者姓名、性别、最高学历、职称、职务、E-mail及联系电话。对文章中的各主要结论，均必须至少有1位作者负责。4 摘要 论著文章须附中、英文摘要，其他栏目的学术论文须附中文摘要。摘要必须包括目的、方法、结果（应给出主要数据）结论四部分。中文摘要200字左右，英文摘要可相对具体些，但不应超过400个实词。5 关键词 所有文章须标引2~5个关键词。请尽量使用美国国立医学图书馆编辑的最新版《Index Medicus》中的医学主题词表（MeSH）内所列的词。如果最新版MeSH中尚无相应的词，可选用直接相关的几个主题词根据树状结构表选用最直接的上位主题词，必要时可采用习用的自由词。6 医学名词 以自然科学名词审定委员会审定公布、科学出版社出版的《医学名词》和相关学科的名词为准，暂未公布的学科仍以人民卫生出版社编的《英汉医学词汇》为准。中文药物名称应使用2005年版药典（法定药物）或卫生部药典委员会编辑的《药名词汇》（非法定药物）中的名称，英文药物名称则采用国际非专利药名，不用商品名。7 图表 每幅图、表应有简明的题目。要合理安排表的纵横标目，并将数据的含义表达清楚；表内数据要求同一指标保留的小数位数相同。图不宜过大，高与宽的比例应掌握在5：7左右。图的类型应与资料性质匹配，并使数轴上的刻度值的标法符合数学原则。照片图要求有良好的清晰度和对比度。8 计量单位 按国务院1984年2月颁布的《中华人民共和国法定计量单位》书写，并以单位符号表示。

兄弟……800字……自己写吧……

建议你去参考教育进展或者创新教育研究这些期刊的文献，上面的论文都是免费下载查阅的哦

你是哪个学校的，班主任叫什么名字？这篇小文章是哪个老师布置的作业？联系方式是什么，我去帮你告状～～～孩子，不管怎么样，搞学术也好，做作业也好，做人也罢。切记，诚实的品质最重要。不是自己的，就不能冠以自己的名字。虽然作业是小事，但是在学术界就会成为丑闻。如果自己会写，并且感兴趣，就应该努力地自己去做，如果来不及写或者不感兴趣，就不要勉强嘛。

Here we present the derivation of the new set of equations termed, Lorentz transformations, and all the subsequent LORENTZ TRANSFORMATIONSWe consider two coordinate systems (frames of reference) one stationary S and one moving at some velocity v relative to S, then according to the two postulates of Relativity, stated in the main text, the displacement in both frames is of the same Therefore, we have (A-1) (A-2)We should note here that in the old Galilean transformations these equations would be (A-3)which is in direct contradiction to Postulate 2, a firm experimental Equations (A-1) and (A-2) can be written as(A-4) (A-5)That is, (A-6)We are interested in finding and in terms of x and That is, = (x, t) (A-7) = (x, t) (A-8)This is accomplished via the formation of two linear simultaneous equations as follows:(A-9) (A-10)where a11, a12, a21, and a22 are constants to be It is required that the transformations are linear in order for one event in one system to be interpreted as one event in the other system; quadratic transformations imply more than one event in the other Solution of problems involving motion begins with an assumption of their initial conditions; , where does the problem begin?The classical assumption is to set = 0 at = Therefore, according to S, the system appears to be moving with a velocity v, so that x = We can obtain this from E (A-9) by writing it in the form = a11(x - vt) so that, when = 0, x = Therefore, we conclude that a12 = - We can write Equations (A-9) and (A-10) as (A-11) (A-12)Substituting and into Equation (A-6) and rearranging, we get (A-13)Since this equation is equal to zero, all the coefficients must That is,(A-14) (A-15) (A-16)Solving these equations we obtain(A-17) (A-18)where β = v/c and Thus, substituting these values in E (A-11) and (A-12) we obtain the famous Lorentz coordinate transformation equations connecting the fixed coordinate system S to the moving coordinate system :(A-19) (A-20)We may also obtain the inverse transformations (from system to S) by replacing v by –v and simply interchanging primed and unprimed This gives,(A-21) (A-22)VELOCITY TRANSFORMATIONSAs a direct consequence to these new transformations, all the other mathematical operations and physical variables follow For example, the velocity equations (though still the derivatives of the displacement) assume a new form, so the Lorentz form of the velocities is:From E (A-19) and (A-20) we have: (A-23) (A-24)Therefore:(A-25)ENERGY CONSIDERATIONSConsider a particle of rest mass m0 being acted by a force F through a distance x in time t and that it attains a final velocity The kinetic energy attained by the particle is defined as the work done by the force F The applicable equations are,(A-26)We note thatand thatSubstituting d(γv) in E (45) and integrating, we obtain (A-27)That is, (A-28)This says that K = (m – m0)c2 and finally one sees that the total energy is equal to the sum of the kinetic energy K and the rest energy E0 = , E = K + Eo = γm0c2 = γE0, (A-29) where E0 = m0c2 and E = 给分吧